HOW TO CALCULATE BRICKS , CEMENT , SAND IN 1 CUM WALL?

Bricks :-

                   The bricks is manufacture in different size but here take a standard size of brick 20x10x10 cm with mortar and without mortar is 19x9x9 cm.

Given Data :-

Mortar thickness  =  10 mm

Ratio of cement & sand. =  1:6

Volume Considere  =   1 cum

Solution :-

Sum of cement and sand =  1+6 => 7

Volume of bricks with mortar  =  20x10x10cm 

                                                          =.002m3 ( change the unit cm to m)

No. of bricks =  volume/ volume of brick

                             1/.002 =  500bricks

Volume of brick without mortar. = 19x9x9cm

                                                           =  .001539m3

Now we know that number of bricks in 1 cum 500 bricks with mortar .then we take 500 bricks volume without mortar

Volume of bricks in 1 cum volume =  500x .001539

                                                                  =  .769cum(m3)

• volume of mortar =  (volume of 1 cum - volume of bricks without mortar)

                                = 1 - .769 => .231 cum(m3)

.231 is the wet volume but we have need dry volume so = .231x1.33 => .30723 cum (m3)

•  CEMENT

           = Volume of mortar x ( cement/sum ratio) x density of cement

              = .30723 x (1/7) x 1440

               =  63.201kg

 

No. of bags = 63.201/ 50

                      =  1.26 bags

•   SAND :- 

                  =  Volume of mortar x ( sand/sum ratio ) x 35.28

                    = .30723 x ( 6/7) x 35.28

                    = 9.29 CFT

•   BRICK

     No. of bricks = 500